May 12, 2015 · The square root of i is (1 + i)/sqrt (2). [Try it out my multiplying it by itself.] It has no special notation beyond other complex numbers; in my discipline, at least, it comes up about …

Nov 25, 2017 · The answer is that there are two square roots of $-1$. This is no different than with real numbers; for example, there are two square roots of $4$: $2$ and $-2$. The main …

The incorrect step is the assumption that $\sqrt {ab} = \sqrt {a} \sqrt {b}$ While this holds for nonnegative numbers, it does not hold for negative numbers. This has to do with the …

Apr 13, 2014 · tl;dr: There are many ways to generalize the square root function to the complex numbers, some of which have $\sqrt {-1} = i$. However, all of them lack some properties of the …

What is the square root of 1? If the square root of 1 is itself then why does other square root of number not equal to themselves? Is there other square root of 1 aside from 1? This question is …

Could someone explain how/why the square root of $x$ equals $x$ to the one half power? I know by definition it does, but is there any mathematical process we can go through to get from one …

Jan 9, 2015 · It is more of a maths question than a pedagogical question so i figured i would ask here instead of MESE. Why is $\sqrt {-1} = i$ and not $\sqrt {-1}=\pm i$? With positive …

Jan 24, 2018 · 7 Why the square root of any decimal number between 0 and 1 always come out to be greater than the number itself? Whereas if we take the square root of say 25 we are left …

Mar 28, 2012 · 16 There are two square roots of $-1$. Using the definite article "the" implies uniqueness. See a related question, which might actually be a duplicate...

@Joe : in the real case there are informal arguments that a square root of 2 should exist. This is the opposite of the situation with -1, where prior concepts suggest that a square root should …